(3x+5)(x-1)-3=3x^2+2x-8

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Solution for (3x+5)(x-1)-3=3x^2+2x-8 equation: 



(3x+5)(x-1)-3=3x^2+2x-8

We move all terms to the left:

(3x+5)(x-1)-3-(3x^2+2x-8)=0

We get rid of parentheses

-3x^2+(3x+5)(x-1)-2x+8-3=0

We multiply parentheses ..

-3x^2+(+3x^2-3x+5x-5)-2x+8-3=0

We add all the numbers together, and all the variables

-3x^2+(+3x^2-3x+5x-5)-2x+5=0

We get rid of parentheses

-3x^2+3x^2-3x+5x-2x-5+5=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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